Question

explain
Determine weother given volves is a zero of the given polynomial


i) x³+3x+2, x=1
ii) x⁴-4x³+6x²-4x+1, x=1
iii) p(x)=2x+1, x=½​

Answer 1

Step-by-step explanation:

ii) x⁴-4x³+6x²-4x+1, x=1 is the answer..

Hope its help..

Answer 2

Answer:

=> X^3 – 3X – 3X^2 + 1 = 0

=>X^3 + 1– 3X – 3X^2 = 0

=>(X^3 + 1) – (3X + 3X^2) = 0

=>(X+1)(X^2 – X + 1) – 3X(1+X) = 0

=>(X+1)( X^2 – 4X + 1) = 0

=>(X+1)( X^2 – 4X + 4-3) = 0

=>(X+1)[( X– 2)^2 - 3)] = 0

(X+1)[( X – 2) + √3)( ( X – 2) - √3)] = 0

▶Hence X = -1 or (2 - √3) or (2 + √3).