Question

EXPLAIN E=MC^2 IN DETAIL.

Answer 1

Heya........


Here is your answer



Let M = mass
       E = energy
       C = speed of light in vacuum
M2 X C2 = (Ml2 + Mw2 +Mmh2)
Adding 4th term energy
M2 X C2 = (Ml2 +Mw2 + MH2) + E2
Normalizing energy by dividing C2
M2 X c2 = (Ml2 + Mw2 + MH2) + E2/C2
At rest momentum is zero
M2 X C2 = 0 + E2/C2
M2 X C2 = E2/C2
M2 X C2 X C2= E2
E2 = M2 X C4
Taking root of the whole equation
√ (E2 = M2 X C4)
E = MC2

Hope it helps ❤️