explain emperical formula with the example
Answers
16. Chemical analysis of a carbon compound gave the following percentage composition by weight of the elements present, carbon = 10.06% , hydrogen = 0.84 % , chlorine = 89.10% . Calculate the empirical formula of the compound.
Answer::
Step 1: Percentage composition of the elements present in the compound.
C H Cl
10.06 0.84 89.10
Step 2: Dividing by the respective atomic weights ofthe elements
C H Cl
10.06/12 0.84/1 89.10/35.5
= 0.84 = 0.84 =2.5
Step 3: Dividing by the smallest number. =0.84
C H Cl
0.84/0.84 0.84 /0.84 2.51/0.84
=1 =1 =3
Step 4: Multiplication by a suitable integer to get whole number ratio.
The empirical formula of the compound is ClHlC13 = CHC13.
Explanation:
the empirical formula of a chemical compound is the simplest positive integer ratio of atoms present in a compound. A simple example of this concept is that the empirical formula of sulfur monoxide, or SO, would simply be SO, as is the empirical formula of disulfur dioxide, S2O2.