Question

explain enthalpy of formation of methane​

Answer 1

Answer:

Here's Your Answer

Explanation:

The standard enthalpy of formation, ΔH∘f , for a given compound is defined as the enthalpy change of reaction when one mole of said compound is formed from its constituent elements in their most stable form. So, you know that the average C−H bond enthalpy is equal to 414 kJ/mol .

Answer 2

Answer:

$here \: your \: anwer$

Explanation:

In your case, the standard enthalpy of formation for methane, CH4 , is calculated for the reaction. C(s]+2H2(g]→CH4(g] Your goal here will be to find a way to get the enthalpy change of reaction for the above reaction by using Hess' Law. So, you know that the average C−H bond enthalpy is equal to 414 kJ/mol .

Hope it's help you..

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