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(a^m ÷ a^n = a^m-n)
Now,
7^2t ÷ 7^t+1 = 7^5
>7^2t-(t+1) = 7^5
>7^2t-t-1 = 7^5
Since the bases are same (all the base numbers are 7) , we can take the powers of the numbers into an equation so as to solve them.
Therefore,
2t - t -1 = 5
> t - 1 = 5
> t = 5 + 1
> t = 6
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