Question

п
explain
find the zeroes of x2-2x-8
and verify the
the relation blu
b/w the heroes and Coefficients​

Answer 1

Step-by-step explanation:

x^2-2x-8=0

x^2-4x+2x-8=0

x(x-4)+2(x-4)=0

(x-4)(x+2)=0

zeroes of the equation are

x-4=0

x=4

x+2=0

x=-2

now, relation between zeroes and coefficient

sum of zeroes= alpha +beta=-coefficient of b/coefficient of a

4+(-2)=2=-b/a=-(-2)/1=1

product of zeroes=alpha*beta=coefficient of c/coefficient of a

4*(-2)=-8=c/a=(-8)/1=-8

thus the relationship between zeroes and the coefficient of the equation is verified

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