Explain four flaws of arithmetic mean.
Answers
Answer:
1. It cannot be located graphically.
2. A single item can bring big change in the result. For example if there are three terms 4, 7, 10 ; X is 7 in this case. If we add a new term 95, the new X is 4+7+10+95/4 = 116/4 = 29. This is a big change as compared to the size of first three terms’ X- .
3. Its value will be effective only if the frequency is normally distributed. Otherwise in case skewness is more, the results become ineffective.
4. In case of open end class intervals we have to assume the limits of such intervals and a little variation in X can take place. Such is not the case with median and mode, and there is no use of the open end intervals in its calculations.
5. Qualitative forms such as Cleverness, Riches etc. cannot give X as data can’t be expressed numerically.
6. X cannot be located by inspection as in the case of mode and median.
7. Sometimes it gives impossible or laughable conclusions, e.g. if there are 60, 50 and 12 students in three classes then average number of students is 60+50+42/3 = 50.67, which is impossible as students can’t be in fractions.