Explain hit and trial method for balancing and unbalanced equation with the help of an example.
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Hit and Trail method: In this method the equation is balanced by trial and error methods. There is no definite rules to balance the equation but simple guessing. Generally hit and trial method is applicable for simple chemical reaction.
H2 + Cl2 → 2HCL
Following step should be noted while balancing a chemical equation:
The atom which occurs at minimum number of places on both sides should be selected first and the one occurring maximum number of times should be taken last of all. Let’s illustrate this by following equation:
Na+ H2O → NaOH +H2
Let’s look at each element, Na and oxygen is in same number in both product and reactant side, but there is two hydrogen atom in reactant side while in product side there is three. So let’s try to balance the number of hydrogen atom.
If we multiply H2O by 2 in L.H.S, then number of hydrogen becomes 4, and that of oxygen becomes 2. IN the product side, if we also multiply NaOH by 2, then total hydrogen becomes 4 and oxygen becomes 2. So hydrogen and oxygen in both side becomes equal, i.e balanced. However, while multiplying NaOH in product side by 2, the number of Na becomes 2 in product side, but it is only one in reactant side. So, to balance this, we again multiply Na in reactant side by two, so that overall number of atoms of element becomes equal.
So, final balanced chemical equation becomes,
2Na + 2H2O → 2NaOH +H2
H2 + Cl2 → 2HCL
Following step should be noted while balancing a chemical equation:
The atom which occurs at minimum number of places on both sides should be selected first and the one occurring maximum number of times should be taken last of all. Let’s illustrate this by following equation:
Na+ H2O → NaOH +H2
Let’s look at each element, Na and oxygen is in same number in both product and reactant side, but there is two hydrogen atom in reactant side while in product side there is three. So let’s try to balance the number of hydrogen atom.
If we multiply H2O by 2 in L.H.S, then number of hydrogen becomes 4, and that of oxygen becomes 2. IN the product side, if we also multiply NaOH by 2, then total hydrogen becomes 4 and oxygen becomes 2. So hydrogen and oxygen in both side becomes equal, i.e balanced. However, while multiplying NaOH in product side by 2, the number of Na becomes 2 in product side, but it is only one in reactant side. So, to balance this, we again multiply Na in reactant side by two, so that overall number of atoms of element becomes equal.
So, final balanced chemical equation becomes,
2Na + 2H2O → 2NaOH +H2
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