Chemistry, asked by katredevendra331, 11 months ago

explain hoffmann's exhaustive methylation

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Answered by uniyalsudhir368
3

Answer:

Exhaustive methylation: The process of alkylation with methyl groups until all possible methylations have been achieved. In the Hofmann eliminationreaction sequence, exhaustive methylation (shown in red) converts an amine to an alkylammonium salt prior to E2 elimination.

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Answered by lisaRohan
2

Answer:

The Hoffman's exhaustive methylation is as follows:

Exhaustive methylation: The process of alkylation with methyl groups until all possible methylations have been achieved. In the Hofmann elimination reaction sequence, exhaustive methylation (shown in red) converts an amine to an alkylammonium salt prior to E2 elimination.

Exhaustive methylation: The process of alkylation with methyl groups until all possible methylations have been achieved. In the Hofmann elimination reaction sequence, exhaustive methylation (shown in red) converts an amine to an alkylammonium salt prior to E2 elimination.Explanation:

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