Question

Explain how 2-chloro-3-methylbutane on treatment with alcoholic potash given 2-methyl but-2ene as

the major product.

Give proper and meaninful answer .
length of the answer shoulb be according to 2 marks.​

Answer 1

Answer:

it is in the attachment given below.....

Hope u get it mate.....

Answer 2

The compound 2-chloro-3-methylbutane on treatment with alcoholic potash given 2-methyl but-2-ene in accordance with the Saytzeff rule.

- This reaction is termed as dehydrohalogenation.

- It is a β- elimination reaction.

- The chloride at 2- position is removed along with the hydrogen from the β- position according to the Saytzeff rule.

CH3-CH(Cl)-CH(CH3)-CH3 + alc. KOH → CH3-CH=C(CH3)-CH3 + HCl

- Hence, 2-methyl but-2-ene is formed as  the major product.