Explain how 2-chloro-3-methylbutane on treatment with alcoholic potash given 2-methyl but-2ene as
the major product.
Give proper and meaninful answer .
length of the answer shoulb be according to 2 marks.
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The compound 2-chloro-3-methylbutane on treatment with alcoholic potash given 2-methyl but-2-ene in accordance with the Saytzeff rule.
- This reaction is termed as dehydrohalogenation.
- It is a β- elimination reaction.
- The chloride at 2- position is removed along with the hydrogen from the β- position according to the Saytzeff rule.
CH3-CH(Cl)-CH(CH3)-CH3 + alc. KOH → CH3-CH=C(CH3)-CH3 + HCl
- Hence, 2-methyl but-2-ene is formed as the major product.
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