explain how 20 bit physical address is generated in 8086 with an example
Answers
Answered by
0
Answer:
Nopeeeeeeeeeeeeeeeeeeeeeeeeeee I will not answer.
Answered by
5
__________________________
Each Segment has a corresponding 16-bit Segment Register which holds the Base Address (starting Address) of the Segment. At any given time, 8086 can address 16-bit x 64KB = 256 KB of memory chunk out of 1MB. 8086 has 20bit address line. So the maximum value of address that can be addressed by 8086 is 2^20 = 1MB.
hope you are...
follow me ✌️❤️✌️
__________________________
Similar questions