Question

explain how Momentum is conserved in case of recoiling of gun ????

Please give right answer .

Class 9 - Force and law of motion .

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Answer 1

Answer:

Explanation:

Conservation of momentum states that the momentum of the body remains conserved if no external force is applied on it.

The state of rest or motion is not disturbed if external force is not applied on it. If external force is applied on the body the state will change with change in its momentum.

Suppose a body is moving in a straight line with a constant speed. The body will continue its motion and the momentum of the body will remain conserved until and unless some external force acts on it. The change in momentum can be observed only when external force acts on the body. Internal force never brings change in the momentum of the body.

Examples of conservation of momentum:

Rocket – Gas system Initially when the rocket is at rest the momentum of the system is zero. When rocket takes off it throws gas in opposite direction to its motion. The magnitude of the velocity of the gas in downward direction is equal to the magnitude of the velocity of rocket in the upward direction. The direction of velocity is in opposite direction therefore the net momentum again comes out to be zero and hence the conservation of momentum.

Bullet fired from the gun Here also initially when no bullet is fired the net momentum of the bullet-gun system has zero momentum. When bullet is fired the magnitude of the velocity of the bullet in forward direction is equal to the magnitude of the velocity of gun in the backward direction. The direction of velocity is in opposite direction therefore the net momentum again comes out to be zero and hence the conservation of momentum. This is the reason why recoil of gun is observed.

i hope this can helpfull

Answer 2

Answer:

Whenever , a bullet is fired from a gun, the gun recoils backwards. This backwards recoil can be explained die to Momentum Conservation in the gun.

Let's take an example :

We are holding a stationary gun. Inside the barrel of the gun, there is a stationary bullet. So we can say that the Initial Momentum for both bullet and Gun is zero because of zero velocity (speed).

Now when you press the trigger , the bullet goes out of the muzzel at a high speed. So now the bullet has some momentum.

Due to conservation of momentum, a similar magnitude of momentum is transmitted to the gun but opposite in Direction.

That's why the Gun recoils backwards , and Recoil velocity is opposite to the direction of velocity of bullet.

Mathematically, it can be proven :

Let mass of bullet be m , mass of gun be M , velocity of bullet be u and Recoil velocity of Gun be v.

$\red{initial \: momentum = final \: momentum}$

$\red{ = > 0 + 0 = ( m \times u) +( M \times v)}$

$\red{ = > ( M v) = - (mu)}$

So final momentum of gun is equal and opposite to that of final momentum of bullet. That's why Momentum is conserved during recoiling of a gun.