Question

Explain how much portion of an atom located at corner and body centre of a unit cell is part of its neighbouring unit cell

Answer 1

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Secondary SchoolChemistry 15 points

Explain how much portion of an atom located at (i) corner and (ii) body-centre of a cubic unit cell is part of its neighbouring unit cell.

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Answer :

(i) In simple cubic only corners are occupied by points. Since each point on a corner is shared by eight unit cells, therefore, a point at the corner of a unit cell contributes only one-eighth ( \frac{1}{8}) to the cell. There are 8 corners each occupied by one point.

Even though a total of \frac{7}{8} part is there with neighbours, one neighbour cell only has \frac{1}{8} part.

Answer 2

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(i)the atom of corner of a cubic unit cell is shared by eight adjacent unit cells.

Therefore, portion of the atom at the corner = 8 × 1/8 = 1 atom.

(ii) The atoms present at the center of the body is not shared by its neighboring unit cell.

Therefore, portion of the atom at the center = 1 atom

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