Explain how much portion of an atom located at (i) corner and (ii) body-centre of a cubic unit cell is part of its neighbouring unit cell.
Answers
Answered by
1
1)1/8th and (2) 100/100 part of it
Answered by
54
(i)the atom of corner of a cubic unit cell is shared by eight adjacent unit cells.
Therefore, portion of the atom at the corner = 8 × 1/8 = 1 atom.
(ii) The atoms present at the center of the body is not shared by its neighboring unit cell.
Therefore, portion of the atom at the center = 1 atom
Similar questions