Question

explain how:

nth term of a given progression be given by

:)tn=an+b

don't give silly answers...plzz:)​

Answer 1

Answer:

Tn =an +b

first term is T1

substituting n=1

an+b

=a+b

T2= a(2)+b

2a+b

T3 =a(3)+b

=3a+b

now , difference between first term and second term is a , difference between second and third term is also a ..therefore in the series we have a common difference of a

Thus the series is an AP series

Hope it helps