Question

explain how potentiometer can be compared emf's of two cell​

Answer 1

Explanation:

Using a potentiometer, we can determine the emf of a cell by obtaining the balancing length l.

Here, the fall of potential along the length l of the potentiometer wire is equal to the emf of the cell, as no current is being drawn from the cell.

Here, the fall of potential along the length l of the potentiometer wire is equal to the emf of the cell, as no current is being drawn from the cell. Then, or, ; where k is the potential gradient along the wire.

Answer 2

Answer:

Using a potentiometer, we can determine the emf of a cell by obtaining the balancing length l. Here, the fall of potential along the length l of the potentiometer wire is equal to the emf of the cell, as no current is being drawn from the cell. Then, or, ; where k is the potential gradient along the wire

Explanation:

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