Explain how the colour of a solution of K 2Cr207
depends on the pH of the solution?
Answers
Answer:
K 2 Cr 2 O 7 is a strong oxidizing agent, it itself gets reduced and oxidizes other compound. It is orange in colour. pH <7 = solution is acidic; orange to yellow due to yellow colour of CrO 42- pH > 7 = Solution is basic ; Yellow to Orange
Explanation:
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Answer:
Potassium dichromate (K
2
Cr
2
O
7
) is a strong oxidising agent which oxidises other compund by reduced itself.
The colour of K
2
Cr
2
O
7
depends on the pH of the solution as if
pH<7 : The solution is acidic. Its colour changes from orange to yellow due to yellow colour of CrO
4
2−
ion.
pH>7 : The solution is basic. Its colour changes from yellow to orange due to orange colour of Cr
2
O
7
2−
ion.
Cr
2
O
7
2−
+H
2
O→2CrO
4
2−
+2H
+