Question

Explain hyperconjugation in propylene molecule

Answer 1

it has 4 hypervonjugated H atoms

Answer 2

Explanation:

In the formalism that separates bonds into σ and π types, hyperconjugation is the interaction of σ-bonds (e.g. C-H, C-C, etc.) with a π network.

This interaction is customarily illustrated by contributing structures, e.g. for toluene (below), sometimes said to be an example of "heterovalent" or "sacrificial hyperconjugation", so named because the contributing structure contains one two-electron bond less than the normal Lewis formula for toluene.