Physics, asked by Anonymous, 10 months ago

EXPLAIN IN DETAIL OTHERWISE I'LL REPORT !!!​

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Answered by Anonymous
3

Answer:

The  \: fact  \: that  \: there \:  is \:  a  \: higher  \: \\  binding  \: energy  \: in \:  the  \: region  \\  \: near \:  A=100 - 200 \: means \:  \\  that  \: either  \: the  \: breakup  o f \:  heavier \:  nuclei  \\ (fission)  \: or \:  the  \:  \: combining  \: of \:  lighter  \:  \\ nuclei  \: (fusion)  \: will  \: yield \:  nuclei  \: which  \\ are  \: more  \: tightly  \: bound \:  (less  \: mass  \: per \:  \\  nucleon) if  \: the  \: atom/s  \: formed \:  lies   \\ \: in \:  this \:  region \:  of  \: stability. \: </p><p>For  \: fusion \\   \: two  \: atoms  \: of  \: atomic \:  mass \:  no.  \: between \:  \\  50 - 100  \: will  \: combine  \: and  \: produce \\  \:  a  \: atomic \:  number \:  of \:  100 - 200  \: and  \: \\  will  \: be  \: stable  \: than \:  individual \: atoms \\  \:  by \:  releasing \:  the  \: energy. \:

Answered by Anonymous
2

\huge\boxed{\underline{\mathcal{\red{A}\green{N}\pink{S}\orange{W}\blue{E}\pink{R}}}}

\huge\boxed{\underline{\mathcal{\red{(3)}\green{B}\pink{and}\orange{D}}}}

</p><p>\huge{\green{\underline{\red{\mathbf{ EXPLANATION}}}}}

Solution :

In fusion, two or more lighter nuclei combine to make a comparatively heavier nucleus.

In fission, a heavy nucleus beaks into two or more comparatively lighter nuclei.

Further, energy will be released in a nuclei process if total binding energy increases.

Hence, correct options are (b) and (d).

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