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AC² = AB² + BC² ( Pythagoras Theorem)
AC ² = (18)² + (24)² = 900
AC² = 900
AC = 30
Now BC² = AC. MC ( BM Perpendicular to AC)
So (24)² = 30 * MC
576 = 30 * MC
MC = 576 / 30 = 19.2
AC = AM + MC
30 = AM +19.2
AM = 30 - 19.2 = 10.8 cm
Now BM²= AM * MC ( BM Perpendicular to AC)
BM²= 10.8 * 19.2
BM²= 207.36
BM = √207.36
BM = 14.4
Hope you like it please mark as brainliest.
AC ² = (18)² + (24)² = 900
AC² = 900
AC = 30
Now BC² = AC. MC ( BM Perpendicular to AC)
So (24)² = 30 * MC
576 = 30 * MC
MC = 576 / 30 = 19.2
AC = AM + MC
30 = AM +19.2
AM = 30 - 19.2 = 10.8 cm
Now BM²= AM * MC ( BM Perpendicular to AC)
BM²= 10.8 * 19.2
BM²= 207.36
BM = √207.36
BM = 14.4
Hope you like it please mark as brainliest.
ShubhGandhi2903:
Hope you like it
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