explain in detail the material used for working finding and desert of Rutherford gold foil scattering also make a diagram
Answers
Answer:
In Rutherford's experiment, generally the thin foil of heavy atoms like gold, platinum etc. have been used to be bombarded by the α-particles. If the thin foil of light atoms like aluminium etc. is used, what difference would be observed from the above results?
Step-by-step explanation:
Heavy nuclei have large positive charges and light nuclei have small positive charges. The repulsion between alpha particles and heavy nuclei is much larger than the repulsion between alpha particles and small nuclei.
More number of alpha-particles will pass as the nucleus of the lighter atoms is small, smaller number of alpha-particles will be deflected as a number of positive charges is less than on the lighter nuclei.
Rutherford passed beams of alpha particles through a thin gold foil to observe the atom and noted how the alpha particles scattered from the foil.
Observations of Rutherford's alpha ray scattering experiment:
1.Most of the α-particles passed straight through the gold foil without any deviation.
2. Some of the α-particles were deflected by the foil by some angles.
3.Interestingly one out of every 12,000 alpha particles appeared to rebound
Conclusion of Rutherford's scattering experiment:
1.Most of the space inside the atom is empty because most of the α-particles passed through the gold foil without getting deflected.
2. Very few particles were deflected from their path, indicating that the positive charge of the atom occupies very little space.
3. A very small fraction of α-particles were deflected by very large angles, indicating that all the positive charge and mass of the gold atom were concentrated in a very small volume within the atom.
:-)
