Math, asked by sindhusharavuri, 1 year ago

explain in detail these questions
for 25 points

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Answers

Answered by DeepikaSrk
2
hi friend here is your answer
in the 2nd answer after
8-12+4
=12-12
=0
hope this helps

do mark as brainliest
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DeepikaSrk: plz mark as brainliest
Answered by abhi178
3
here some mistake in writing .
I think P(x) = acx²+ ( ab -c²)x -bc

now,

acx² + (ab - c²)x - bc

= acx² + abx - c²x - bc

= ax ( cx + b) - c ( cx + b)

=( ax - b)( cx+ b)

hence, p(x ) = (ax - b) ( cx + b)
for zero ,
P(x ) = 0
then,
x = b/a and -b/c

2) x³ -3x² +2x =0

= > x( x² -3x +2)

=> x( x -2)( x -1)

x(x -1)(x -2) =0

x = 0, 1 and 2

3) p( y) =7 y² -11y/3 -2/3

for finding of roots

7y² -11y/3 -2/3 =0
21y² -11y -2 =0

use formula for finding roots
x ={ 11±√(121 +168)}/14
=( 11 ±17)/14

= 2, -6/14

= 2, -3/7

abhi178: see the answer ,
abhi178: now refresh it , i edit this
abhi178: i hope this will be helped you
abhi178: thanks for marking brainliest nice of you
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