Explain in easy words:
Normality Equation (80 words)
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Normality :- no of gram equivalent of solute present in 1 L of a solution .
first of all , what is gram - equivalent ??
gram-equivalent :- it is the ratio of given weight of substance and equivalent weight .
example :- what is the gram equivalent of 2.7 g of aluminum .??
gram equivalent = given weight/ equivalent wt
we know, equivalent wt = molecular wt/n-factor
for Al equivalent wt = 27/3 = 9 g
now , gram equivalent = 2.7/9 = 0.3
================================
Normality = no of gram equivalent of solute per unit volume of solution .
so,
N = gram equivalents/V( L)
= (Ws/Es)/V( L)
= Ws × 1000/(M/n) × V(ml)
=n× Ws× 1000/M × V(ml)
we know, ws/M = no of mole
we also know , no of mole per unit volume = molarity
so,
Normality = n× molarity
e.g N = n× M
example :- a solution of H2SO4 which molarity is 2M then what is Normality ??
Normility = n × M
we know ,
n - factor of H2SO4 is 2 then .
Normality = 2×2 = 4 N
first of all , what is gram - equivalent ??
gram-equivalent :- it is the ratio of given weight of substance and equivalent weight .
example :- what is the gram equivalent of 2.7 g of aluminum .??
gram equivalent = given weight/ equivalent wt
we know, equivalent wt = molecular wt/n-factor
for Al equivalent wt = 27/3 = 9 g
now , gram equivalent = 2.7/9 = 0.3
================================
Normality = no of gram equivalent of solute per unit volume of solution .
so,
N = gram equivalents/V( L)
= (Ws/Es)/V( L)
= Ws × 1000/(M/n) × V(ml)
=n× Ws× 1000/M × V(ml)
we know, ws/M = no of mole
we also know , no of mole per unit volume = molarity
so,
Normality = n× molarity
e.g N = n× M
example :- a solution of H2SO4 which molarity is 2M then what is Normality ??
Normility = n × M
we know ,
n - factor of H2SO4 is 2 then .
Normality = 2×2 = 4 N
Anonymous:
Thanks for helping^_^
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