Question

Explain in steps please..

Answer 1

during first second

V = u + at

v = o + 2(1)

v =2m/s

$s = ut + \frac{1}{2}at^{2}$

s = 1/2 ( 2(1))

$s_{1}$ = 1m

during the t =2

v = u + at                           a = 0  -diagram

v = 2m/s

s = [2(1)]

$s_{2}$ = 2m              

during t = 3

$s_{3}$ = [2(1) + 1/2(-2)]

$s_{3}$ = 1m

total distance  = 4m

Brainliest please