Question

Explain it also please.
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Answer 1

☆ Perimeter of square = 24 m

☆ Let side of square be 'x' m

$\tt\implies \:4x = 24 \\ \tt\implies \:x \: = \: 6 \: m$

$\therefore \: \tt \:  Area \: of \: square \: = {x }^{2} = {6}^{2} = 36 \: {m}^{2}$

☆ Perimeter of square = 32 m

☆ Let side of square be 'y' m

$\tt\implies \:4y = 32 \\ \tt\implies \:y \: = \: 8 \: m$

$\therefore \:\tt \:  Area \: of \: square \: = {y}^{2} = {8}^{2} = 64 \: {m}^{2}$

☆ Let side of square whose area is equal to sum of areas of above two squares be 'z' m.

$\tt\implies \: {z}^{2} = 36 + 64$

$\tt\implies \: {z}^{2} = 100$

$\tt\implies \:z = 10 \: m$

$\therefore \:\tt \:  Perimeter \: of \: square \: = 4z$

$\tt\implies \:  Perimeter \: of \: square \: = 4 \times 10 = 40 \: m$