Math, asked by zakas, 10 months ago

explain it if any one give correct explanation then I will mark answer as brain list answer​

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Answered by rithvik301
2

Answer:

Step-by-step explanation:

x+ay+a=0a (xa+y+1)=0xa+y+1=0   ... (1)

bx+y+b=0b (x+yb+1)=0x+yb+1=0   ... (2

cx+cy+1=0c (x+y+1c)=0x+y+1c=0   ... (3)

Subtracting (1) from (3) ,

we get x−xa+1c−1=0x (a−1a)=c−1cx=c−1a−1 . ac

Subtracting (2) from (3) ,

we get y−yb+1c−1=0y (b−1b)=c−1cy=c−1b−1 . bc

Substituting the value of x and y in (3) ,

we get c−1a−1 . ac+c−1b−1 . bc+1c=0c−1c (aa−1+bb−1+1c−1)=0 aa−1+bb−1+1c−1=0aa−1+bb−1+1c−1+1=1aa−1+bb−1+1+c−1c−1=1aa−1+bb−1+cc−1=1    ANS...Correct option is C.

Answered by bhoslelaxman250
1

hope it's help you guy's......

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