Question

Explain it in elaborated way please ​

Answer 1

Answer:

Write 28-16\sqrt{3}28−163 as (1)^{4}-4(1)^{3}(\sqrt{3})+6(1)^{2}(\sqrt{3})^{2}-4(1)(\sqrt{3})^{3}+(\sqrt{3})^{4}(1)4−4(1)3(3)+6(1)2(3)2−4(1)(3)3+(3)4 .

This is expansion of (1-\sqrt{3})^{4}(1−3)4 .

Hence, answer is (1-\sqrt{3})(1−3)