explain it please ....
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Answer:
Step-by-step explanation:
L.H.S. = (a+b+c)*(a-b+c)
=(ck² + ck + c) ((ck² - ck + c)
= c²(k²+k+1)(k²-k+1)
= c²(k^4-k³+k²+k³-k²+k+k²-k+1)
= c2(k^4 + k² +1)
= c²k^4 + c²k² +c²
= a² + b² + c²
Sanya729:
in the third line if you are separating c² from c... how could it be 1 ??
please explain me last second line.... Pls pls
Answered by
3
They've complicated things. It's easier this way:
a/b = b/c
→ b² = ac ---------(i)
LHS = (a+b+c)(a-b+c)
= ((a+c)+b)((a+c)-b)
= (a+c)² - b² {(x-y)(x+y) = x²-y²}
= a² + c² + 2ac - b²
= a² + c² + 2b² - b² (From (i))
= a² + b² + c² = RHS
a/b = b/c
→ b² = ac ---------(i)
LHS = (a+b+c)(a-b+c)
= ((a+c)+b)((a+c)-b)
= (a+c)² - b² {(x-y)(x+y) = x²-y²}
= a² + c² + 2ac - b²
= a² + c² + 2b² - b² (From (i))
= a² + b² + c² = RHS
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