Question

explain it with steps$\frac{x^{2000} + x^{1999}}{ x^{2000}- x^{1998} }$

Answer 1

→ $\frac{x^{1999}(x+1)}{x^{1998}(x-1)(x+1)}$
→ $\frac{x}{x-1}$

Answer 2

Answer:

$→ \frac{x^{1999}(x+1)}{x^{1998}(x-1)(x+1)}x1998(x−1)(x+1)x1999(x+1)</p><p>→ \frac{x}{x-1}x−1x</p><p>$