Question

explain its clearly and don't scam​

Answer 1

$\sf\blue{To \: Find:-}$

$\sf{ a = ? }$

$\sf{ b = ? }$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \:$

$\sf\blue{Method \: Used:-}$

$\sf{Rationalising \: Denominator}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \:$

$\sf\blue{Formula \: Used:-}$

$\sf{(a - b)(a + b) = {a}^{2} - {b}^{2} }$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \:$

$\sf\blue{Solution:-}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \:$

$\sf{ \frac{3 + 2 \sqrt{2} }{3 - \sqrt{2} } = } \sf \blue{ \: a \: + \: b \sqrt{2} }$

$\sf{ \frac{3 + 2 \sqrt{2} }{3 - \sqrt{2} } \times \frac{3 + \sqrt{2} }{3 + \sqrt{2} } = } \sf \blue{ \: a \: + \: b \sqrt{2} }$

$\sf{ \frac{(3 + 2 \sqrt{2} )(3 + \sqrt{2} )}{ {(3)}^{2} - ( \sqrt{2})^{ \cancel2} } = } \sf \blue{ \: a \: + \: b \sqrt{2} }$

$\sf{ \frac{3(3 + \sqrt{2}) + 2 \sqrt{2} (3 + \sqrt{2}) }{3 - 2 } = } \sf \blue{ \: a \: + \: b \sqrt{2} }$

$\sf{ \frac{9 + 3\sqrt{2} + 6 \sqrt{2} + 2 {( \sqrt{2}) }^{2} }{3 - 2 } = } \sf \blue{ \: a \: + \: b \sqrt{2} }$

$\sf{ \frac{9 + 9 \sqrt{2} + 4 }{1 } = } \sf \blue{ \: a \: + \: b \sqrt{2} }$

$\sf{ 13 + 9 \sqrt{2} = } \sf \blue{ \: a \: + \: b \sqrt{2} }$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \:$

$\sf{Comparing \: Values}$

$\sf \blue{a = 13 }$

$\sf \blue{b =9 }$

Answer 2

Step-by-step explanation:

Given :-

2x² - 4x + 5

To Find :-

1/α + 1/β

(α - β)²

Solution :-

We know that

Sum of zeroes = -b/a

Here

b = -4

a = 2

-(-4)/2

4/2

2/1

2

Product of zeroes = c/a

c = 5

a = 2

5/2

Now

1/α + 1/β = α + β/αβ

= 2/(5/2)

= 2/5 × 2/1

= 4/5

b)

We know that

(α - β)² = (α + β)² - 4αβ

(2)² - 4(5/2)

4 - 20/2

8 - 20/2

-12/2

-6