Question

Explain Kirchhoff s law and obtain necessary condition for balancing state of

wheat-Stone bridge with the help of it.​

Answer 1

Answer:

Kirchhoff had given two laws :

First law (junction theorem): The algebraic sum of all the currents meeting at a junction is always equal to zero.

Sign Convection: the currents flowing towards the junction are taken as positive and the currents flowing out of the junction are taken as negative.

Second law (loop theorem): The algebraic sum of product of potential and currents is always equal to zero;sum of all e.m.f is equal to zero.

Condition for balancing of wheatstone bridge:

Wheat Stone is balanced when K1 key is closed and then k2 key, the galvanometer shows no deflection.

In this the ratio of resistances in different arms is equal

P/Q = R/S

where P,Q,R,S are resistances

Answer 2

Kirchhoff s law and balancing state of the Wheatstone bridge is as follows:-

• The algebraic total of all voltages in a closed-loop circuit equals zero, according to Kirchhoff's Voltage Law. This means that the algebraic total of all voltage dips across all resistors, capacitors, and inductors, as well as all voltage, rises across all voltage supplies, is zero.
• The algebraic sum of all currents entering and leaving a node equals zero, according to Kirchhoff's Current Law. What goes in must come out, in other words.
• Wheatstone bridge is an electrical circuit that is used to accurately measure a conductor's resistance.
• It is based on Kirchhoff's laws as it involves the algebraic total of all voltages and currents in four resistors are linked in series to form a closed loop. When no current passes through the coil and the potential difference across the galvanometer is zero, the bridge is in balance.