Question

explain law of conservation of energy in the case of freely falling object in detail

Answer 1

Law of conservation of energy states that the energy can neither be created nor destroyed but can be transformed from one form to another. Let us now prove that the above law holds good in the case of a freely falling body. Let a body of mass 'm' placed at a height 'h' above the ground, start falling down from rest

Answer 2

$\huge{HEY!!}$
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⭕This law states that energy can neither be created nor destroyed. It can only be converted from one form to another.

⭕Suppose an object of mass m Falls freely from a height h.

⭕At the start, the potential energy is mgh and kinetic energy is zero. The kinetic energy is zero because its velocity is zero. The total energy of the object is mgh.

⭕As it fall, its potential energy will change into kinetic energy. 

⭕If V is the velocity of the object at a given instant, the kinetic energy would be 1/2 mv^2.

⭕As the fall continuous, potential energy would decrease while the kinetic energy would increase.

⭕When the object is about to reach the ground h = 0 and V will be the highest, the kinetic energy would be largest and the potential energy will be the least.

⭕However, the sum of the potential energy and kinetic energy of the object would be the same at all the points.

⭕Potential energy + Kinetic energy = Constant
mgh + 1/2mv^2 = constant. 

⭕The sum of kinetic energy and potential energy of an object is called the total mechanical energy.