Question

explain law of conservation of momentum and derive its mathematical expression with the help of third law of motion PLS DO IT FAST ANYONE

Answer 1

hey,
i think the soution is right
or an also

Answer 2

Hey there,

The total mometum of the system i s always constant (i e) when the impulse due to external forces is zero, the momentum of the system remains constant . This is known as Law of Conservation of Momentum.

Now F1 acting on the body B for a time t, changes its velocity from u2 to v2.
F1 =  mass of the body B * acceleration of the body B
= m2 * (v2-u2)/ t

Similarly, F2 acting on the body A for the same time t changes its velocity from u1 to v1
= m1* (v1-u1)/t

Then by Newton's third law of motion F1 = -F2

m2* (v2- u2)/t = - m1* ( v1 - u1)/t
m2( v2- u2) = -m1 (v1- u1)
m2v2- m2u2 = -m1v1 + m1u1
m1u1 + m2u2 = m1v1 + m2u2

The total momentum before impact = total momentum after impact
Total momentum of the system is conserved.

This proves the law of conservation of momentum using Newton's 3rd law.


Hope it helps....

















m2 ( v2- u2) =