Question

Explain law of multiple proportion with two examples

Answer 1

Answer:

Two different compounds are formed by the elements carbon and oxygen. The first compound contains 42.9% by mass carbon and 57.1% by mass oxygen. The second compound contains 27.3% by mass carbon and 72.7% by mass oxygen. Show that the data are consistent with the Law of Multiple Proportions.

Solution

The Law of Multiple Proportions is the third postulate of Dalton's atomic theory. It states that the masses of one element which combine with a fixed mass of the second element are in a ratio of whole numbers.

Therefore, the masses of oxygen in the two compounds that combine with a fixed mass of carbon should be in a whole-number ratio. In 100 g of the first compound (100 is chosen to make calculations easier) there are 57.1 g O and 42.9 g C. The mass of O per gram C is:

57.1 g O / 42.9 g C = 1.33 g O per g C

In the 100 g of the second compound, there are 72.7 g O and 27.3 g C. The mass of oxygen per gram of carbon is:

72.7 g O / 27.3 g C = 2.66 g O per g C

Dividing the mass O per g C of the second (larger value) compound:

2.66 / 1.33 = 2

Which mean that the masses of oxygen that combine with carbon are in a 2:1 ratio. The whole-number ratio is consistent with the Law of Multiple Proportions.

Answer 2

LAW OF MULTIPLE PROPORTION--------------~~~~~~~~~~~

according to it when two elements combined to form two or more than two chemical compounds then the mass of one element has simple whole number ratio or same ratio.

EXAMPLES---------------~~~~~~~~~~~

REFER TO ATTACHMENT.......

1》 example of combination of carbon and oxygen is given as carbon dioxide(CO2) and carbon mono oxide(CO).

2》 example of of combination of Sulphur and oxygen as Sulphur dioxide(SO2) and sulphur trioxide(SO3)

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