Question

explain magnification of mirror and lens​

Answer 1

Answer:

The mirror formula

1f=1v+1u

Where

f

is the focal length of the mirror,

u

is the distance of the object from the mirror and

v

is the distance the image is formed from the mirror.

m=−vu

The size of an object’s image is larger (or smaller) than the object itself by its magnification,

M

. The level of magnification is proportional to the ratio of

v

and

u

. An image that is double the size of the object would have magnification

M=2

.

R=2f

The radius of curvature of a mirror is twice its focal length.

Example 1

In the situation illustrated below, the object is set up .5 m away from a converging mirror. If the focal length of the lens is .2 m, determine a) the location of the real image, and b) the magnification of the image.

Explanation:

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Answer 2

Magnification:

↪linear magnification

the linear magnification produced by a mirror is equal to the ratio of the image distance to the object distance, with minus sign.

m = (-v/u)

m = maginifacation

v= image distance

and u = object distance

↪ longitudinal magnification:

when an object lies along the principal Axis then its magnification known as longitudinal magnification, for small objects it is given by ;

m=( -dv/du)

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