Question

Explain Me About Temprature scales (4), conversion of temperature from one to another, related things. Please explain, If spammed I will report ur id

Answer 1

Different Scales on Temperature

They are following Four Scales of Temperature in Common Uses :

• Celsius Scale or Centigrade Scale
• Fahrenheit Scale
• Kelvin Scale or Absolute Scale
• Reaumur Scale

Celsius Scale or Centigrade Scale :

This scale was devised by Anders Celsius in the year 1710. On this scale, ice point is taken as 0°C and steam point is taken as 100°C. the fundamental interval is divided into 100 equal parts (divisions). Each division corresponds to a difference of temperature of 1°C (one degree of Celsius).

Note : A Degree on Celsius Scale is $\rm{\dfrac{1}{100}}$ th part of the Interval between the Ice Point and Melting Point

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Fahrenheit Scale :

This scale was devised by Gabriel Fahrenheit in the year 1717. On this scale, ice point is taken as 32°F and steam point is taken as 212°F. The fundamental interval is divided into 180 equal parts (division). Each division corresponds to a difference of temperature of °F (One degree of Fahrenheit).

Note : A Degree on Fahrenheit Scale is $\rm{\dfrac{1}{180}}$ th part of the Interval between the Ice Point and Melting Point

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Kelvin Scale or Absolute Scale :

This sale of temperature was given by Lord Kelvin (1824- 1907) and is also known as Kelvin scale of temperature. On this scale, ice point is taken as 273 K and steam point is taken as 373 K. the fundamental interval is divided into 100 equal parts (division). Each division corresponds to one Kelvin.

Note : A Degree on Kelvin Scale is $\rm{\dfrac{1}{100}}$ th part of the Interval between the Ice Point and Melting Point. The Size of 1 degree on Kelvin Scale is same as Size of 1 degree on Celsius Scale.

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Reaumur Scale :

This scale was devised by RA. Reaumur in the year 1730. The interval between the lower and the upper fixed points is divided into 80 equal parts. Each division is called one degree Reaumur (1°R). on this scale, the melting point of ice at normal pressure is 0°R. This is lower fixed point. The boiling point of water at normal pressure is 80°R. This is the upper fixed point.

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Absolute Zero of Temperature

The Temperature of - 273°C or zero degree on Kelvin Scale is called as "Absolute Zero" of Temperature. It is lowest Attainable Temperature.

• 0°C = 0 + 273 K = 273 K - 273°C = -273 + 273 K = 0 K

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Parameters of Different Temperature Scales

$\boxed{\begin {array}{c|c|c|c}\sf Temperature \:Scale &\sf Ice\:point &\sf Steam \;point &\sf No\;of\:division\:on\:Fundamental\;interval \\ \frac {\qquad\qquad\qquad}{} &\frac{\qquad\qquad\qquad}{} & \frac {\qquad\qquad\qquad}{} & \frac {\qquad\qquad\qquad\qquad\qquad\qquad}{} \\ \sf Celsius\;scale & 0^\circ C & 100^\circ C & 100\\&&&\\ \sf Fahrenheit\:scale & 32^\circ F & 212^\circ F & 180 \\&&&\\ \sf Kelvin\;scale &273K & 373K & 100\\&&&\\ \sf Reaumer \:scale & 0^\circ R & 80^\circ R & 80\end {array}}$

Note : Ice Point is known as Lower Fixed Point and Steam Point is known as Upper Fixed Point

$\sf \boxed{\begin{tabular}{c|c|c|c}Temperature scale & Ice point (LFP) & Steam point (UFP) & N \\\cline{1-4}Celsius scale & 0^{\circ} C & 100^{\circ} C & 100 \\\cline{1-4} Fahrehneit scale & 32^{\circ} F & 212^{\circ} F &180\\\cline{1-4}Kelvin Scale&273 K&373 K & 100 \\\cline{1-4}Reaumar scale & 0^{\circ} R & 80^{\circ} R & 80 \end{tabular}}$

Where : 'N' is the Number of Division on Fundamental Interval

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Conversion of Temperature From One Scale to Another Scale

Whatever may be the scale of temperature used from Experiments it is concluded that,

$\rm{\dfrac{Thermometer\:Reading\:-\:Lower\:Fixed\:Point}{Number\:of\:Divisions}=Constant}$

Therefore, In order to Convert Temperature from One scale to another, following relation is used.

$\rm{\dfrac{Temparature\:on\:Other\:Scale\:-\:Lower\:Fixed\:Point}{Upper\:Fixed\:Point\:-\:Lower\:Fixed\:Point}}$

$\to\rm{\displaystyle\frac{Temparature\:on\:First\:Scale\:-\:LFP}{UFP\:-\:LFP}=\frac{Temparature\:on\:Second\:Scale\:-\:LFP}{UFP\:-\:LFP} }$

Therefore :

$\boxed{\rm{\displaystyle\frac{C-0}{100-0}=\frac{F-32}{212-32}=\frac{K-273}{373-273}=\frac{R-0}{80-0}}}$

$\to\rm{\displaystyle\frac{C}{100}=\frac{F-32}{180}=\frac{K-273}{100}=\frac{R}{80}}$

When We Multiply The Whole with 20

$\to\rm{\displaystyle\frac{C}{100}\times 20=\frac{F-32}{180}\times 20=\frac{K-273}{100}\times 20=\frac{R}{80}\times 20}$

$\to\boxed{\boxed{\rm{\displaystyle\frac{C}{5}=\frac{F-32}{9}=\frac{K-273}{5}=\frac{R}{4}}}}$

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