Question

explain me how that 1 atomic mass unit is equivalent to about 931 mega electron volts ???

Answer 1

$\huge \mathfrak {Answer:-}$

1 a.m.u = 1.66 x 10-27 kg.

According to Einstein, mass energy equivalenceE = mc2

Where,

m = 1.66 x 10-27 kg.

C = speed of light = 3 x108 m/sec

We get,

E = 1.49 x 10-10 J (1MeV = 1.6 x 10-13 J)

E = 931.25 MeV.

Hence a change in mass by 1a.m.u (called mass defect) releases an energy.

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Answer 2

1 a.m.u = 1.66 x 10-27 kg.

According to Einstein, mass energy equivalenceE = mc2

Where,

m = 1.66 x 10-27 kg.

C = speed of light = 3 x108 m/sec

We get,

E = 1.49 x 10-10 J (1MeV = 1.6 x 10-13 J)

E = 931.25 MeV.