explain me please in this and ans
Attachments:
Answers
Answered by
0
AB would be the diameter of the shaded circle (shift it parallel)
d=40m
r=20 m
A=πr^2
A=π20 × 20
thus area of shaded portion is 400pi sq.mt
d=40m
r=20 m
A=πr^2
A=π20 × 20
thus area of shaded portion is 400pi sq.mt
Similar questions