Question

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Answer 1

Question :

A 6Ω resistance is connected in the left gap of a meter bridge. In the second gap 3Ω and 6Ω are joined in parallel. The balance point of the bridge is at ___

Answer :

Let distance of null point from point A be x cm$.$

Therefore distance of null point from point B will be (100 - x) cm.

In meter bridge, if balance point is obtained at x cm from the zero end, then

• R₁ / R₂ = x / (100 - x)

Where R₁ denotes resistance in the first gap and R₂ denotes resistance in the second gap.

Equivalent resistance of second gap :

➝ R = 3 × 6 / (3 + 6)

➝ R = 18/9

➝ R = 2Ω

By substituting the values, we get

⭆ 6 / 2 = x / (100 - x)

⭆ 3(100 - x) = x

⭆ 300 = 4x

⭆ x = 75 cm

∴ The balance point of the bridge is at 75 cm from zero end.

Answer 2

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Let distance of null point from point A be x cm..

Therefore distance of null point from point B will be (100 - x) cm.

In meter bridge, if balance point is obtained at x cm from the zero end, then

• R₁ / R₂ = x / (100 - x)

Where R₁ denotes resistance in the first gap and R₂ denotes resistance in the second gap.

Equivalent resistance of second gap :

➝ R = 3 × 6 / (3 + 6)

➝ R = 18/9

➝ R = 2Ω

By substituting the values, we get

⭆ 6 / 2 = x / (100 - x)

⭆ 3(100 - x) = x

⭆ 300 = 4x

⭆ x = 75 cm

∴ The balance point of the bridge is at 75 cm from zero end.