Math, asked by EeshanKukreja, 3 months ago

explain me the trigonometry table?​

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Answered by jyotibodke8665
1

if you will observe the table neatly you can see few things,like

the numbers written for sin are written for cos but in the reverse order

same of cosec to sec

the numbers written for tan are written for cot but in multiplicative inverse.


jyotibodke8665: yes,of course
jyotibodke8665: where should I give the answer
jyotibodke8665: in the comment box or edit the answer
EeshanKukreja: wherever you like it
jyotibodke8665: the numerator of sin and the denominator of cos are taken as numerator and denominator of tan resp.
jyotibodke8665: same of sec and cosec for cot
jyotibodke8665: that means if you will only learn the sin ,you can take out the values of cos,tan,sec,cosec,cot
jyotibodke8665: that's all
jyotibodke8665: if you like the answer then make a click on like option
jyotibodke8665: and mark me brainlist answer
Answered by Anonymous
4

\begin{lgathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\sf Trigonometry\: Table \\ \begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\boxed{\begin{array}{ |c |c|c|c|c|c|} \bf\angle A & \bf{0}^{ \circ} & \bf{30}^{ \circ} & \bf{45}^{ \circ} & \bf{60}^{ \circ} & \bf{90}^{ \circ} \\ \\ \rm sin A & 0 & \dfrac{1}{2}& \dfrac{1}{ \sqrt{2} } & \dfrac{ \sqrt{3}}{2} &1 \\ \\ \rm cos \: A & 1 & \dfrac{ \sqrt{3} }{2}& \dfrac{1}{ \sqrt{2} } & \dfrac{1}{2} &0 \\ \\ \rm tan A & 0 & \dfrac{1}{ \sqrt{3} }&1 & \sqrt{3} & \rm \infty \\ \\ \rm cosec A & \rm \infty & 2& \sqrt{2} & \dfrac{2}{ \sqrt{3} } &1 \\ \\ \rm sec A & 1 & \dfrac{2}{ \sqrt{3} }& \sqrt{2} & 2 & \rm \infty \\ \\ \rm cot A & \rm \infty & \sqrt{3} & 1 & \dfrac{1}{ \sqrt{3} } & 0 \end{array}}}\end{gathered}\end{gathered}\end{gathered} \end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered} \end{gathered}\end{gathered}\end{gathered}\end{lgathered}

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