Math, asked by fasaliya7, 3 months ago

Explain me this chapter
TRIANGLE AND ITS PROPERTIES... 7th standard

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Answers

Answered by tummakeerthana19
1

Answer:

go through YouTube....

u will find good videos for explanation.....

Answered by hiyasatra0504
1

Answer:

Medians of a Triangle

Altitudes of a Triangle

Exterior Angle of a Triangle and Its Property

Angle Sum Property of a Triangle

Two Special Triangles: Equilateral and Isosceles

Sum of the Lengths of Two Sides of A Triangle

Right-Angled Triangles and Pythagoras Property

1. In Δ PQR, D is the mid-point of NCERT Solutions for Class 7 Maths Chapter 6 The Triangles and Its Properties Image 1.

Solution:-

Altitude

An altitude has one end point at a vertex of the triangle and other on the line containing the opposite side.

(ii) PD is ___.

Solution:-

Median

A median connects a vertex of a triangle to the mid-point of the opposite side.

(iii) Is QM = MR?

Solution:-

No, QM ≠ MR because, D is the mid-point of QR.

2. Draw rough sketches for the following:

(a) In ΔABC, BE is a median.

Solution:-

A median connects a vertex of a triangle to the mid-point of the opposite side.

NCERT Solutions for Class 7 Maths Chapter 6 The Triangles and Its Properties Image 4

(b) In ΔPQR, PQ and PR are altitudes of the triangle.

Solution:-

NCERT Solutions for Class 7 Maths Chapter 6 The Triangles and Its Properties Image 5

An altitude has one end point at a vertex of the triangle and other on the line containing the opposite side.

(c) In ΔXYZ, YL is an altitude in the exterior of the triangle.

Solution:-

NCERT Solutions for Class 7 Maths Chapter 6 The Triangles and Its Properties Image 6

In the figure we may observe that for ΔXYZ, YL is an altitude drawn exteriorly to side XZ which is extended up to point L.

3. Verify by drawing a diagram if the median and altitude of an isosceles triangle can be same.

Solution:-

NCERT Solutions for Class 7 Maths Chapter 6 The Triangles and Its Properties Image 7

Draw a Line segment PS ⊥ BC. It is an altitude for this triangle. Here we observe that length of QS and SR is also same. So PS is also a median of this triangle.

Exercise 6.2 Page: 118

1. Find the value of the unknown exterior angle x in the following diagram:

(i)

NCERT Solutions for Class 7 Maths Chapter 6 The Triangles and Its Properties Image 8

Solution:-

We Know That,

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

= x = 50o + 70o

= x = 120o

(ii)

NCERT Solutions for Class 7 Maths Chapter 6 The Triangles and Its Properties Image 9

Solution:-

We Know That,

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

= x = 65o + 45o

= x = 110o

(iii)

NCERT Solutions for Class 7 Maths Chapter 6 The Triangles and Its Properties Image 10

Solution:-

We Know That,

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

= x = 30o + 40o

= x = 70o

(iv)

NCERT Solutions for Class 7 Maths Chapter 6 The Triangles and Its Properties Image 11

Solution:-

We Know That,

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

= x = 60o + 60o

= x = 120o

(v)

NCERT Solutions for Class 7 Maths Chapter 6 The Triangles and Its Properties Image 12

Solution:-

We Know That,

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

= x = 50o + 50o

= x = 100o

(vi)

NCERT Solutions for Class 7 Maths Chapter 6 The Triangles and Its Properties Image 13

Solution:-

We Know That,

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

= x = 30o + 60o

= x = 90o

2. Find the value of the unknown interior angle x in the following figures:

(i)

NCERT Solutions for Class 7 Maths Chapter 6 The Triangles and Its Properties Image 14

Solution:-

We Know That,

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

= x + 50o = 115o

By transposing 50o from LHS to RHS it becomes – 50o

= x = 115o – 50o

= x = 65o

(ii)

NCERT Solutions for Class 7 Maths Chapter 6 The Triangles and Its Properties Image 15

Solution:-

We Know That,

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

= 70o + x = 100o

By transposing 70o from LHS to RHS it becomes – 70o

= x = 100o – 70o

= x = 30o

(iii)

NCERT Solutions for Class 7 Maths Chapter 6 The Triangles and Its Properties Image 16

Solution:-

We Know That,

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

The given triangle is a right angled triangle. So the angle opposite to the x is 90o.

= x + 90o = 125o

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