Math, asked by tapandash1974, 4 months ago

explain newton's first law of motion with the help of mathematical expression of Newton's second law of motion​

Answers

Answered by Anonymous
9

Answer:

Newton's first law states that a body stays at rest if it is at rest and moves with a constant velocity unit if a net force is applied on it.

Step-by-step explanation:

Newton’s Second Law of Motion ↴

The second law of motion describes what happens to the massive body when acted upon by an external force. The 2nd law of motion states that the force acting on the body is equal to the product of its mass and acceleration.

  • Newton’s 2nd law states that the acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.

Mathematically, we express the second law of motion as follows ✑

f\propto \frac{dP}{dt}\\ \\ \Rightarrow f\propto \frac{mv-mu}{t}\\ \\ \Rightarrow f\propto\frac{m(v-u)}{t}\\ \\ \Rightarrow f\: \propto \: ma\\ \\ \Rightarrow f=k\, ma

Attachments:
Answered by sumansikhwal890
0

Step-by-step explanation:

Newton's first law ➪ states that a body stays at rest if it is at rest and moves with a constant velocity unit if a net force is applied on it.

Step-by-step explanation:

Newton’s Second Law of Motion ↴

The second law of motion describes what happens to the massive body when acted upon by an external force. The 2nd law of motion states that the force acting on the body is equal to the product of its mass and acceleration.

Newton’s 2nd law states that the acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.

Mathematically, we express the second law of motion as follows ✑

f∝dPdt⇒f∝mv−mut⇒f∝m(v−u)t⇒f∝ma⇒f=kma\begin{lgathered}f\propto \frac{dP}{dt}\\ \\ \Rightarrow f\propto \frac{mv-mu}{t}\\ \\ \Rightarrow f\propto\frac{m(v-u)}{t}\\ \\ \Rightarrow f\: \propto \: ma\\ \\ \Rightarrow f=k\, ma\end{lgathered}

f∝

dt

dP

⇒f∝

t

mv−mu

⇒f∝

t

m(v−u)

⇒f∝ma

⇒f=kma

Similar questions