explain newton’s second law of motion. also derive the relationship between the force applied and the acceleration produced in the body.
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Newton’s second law;
Newton’s second law of motion states that the rate of change of momentum of an object is Proportional to the applied unbalanced force in the direction of force.
Prooving--
Suppose an object of mass, m is moving along a straight line with an initial velocity, u. It is uniformly accelerated to velocity, v in time, t by the application of a constant force, F throughout the time t.
The initial and final momentum of the object will be, p1 = mu and p2 = mv respectively.
The change in momentum = p2 – p1
Then
change in momentum = mv – mu
The change in momentum = m × (v – u).
The rate of change of momentum = m × (v – u)/t
the applied force, F ∝ m × (v – u)/t
F = km × (v – u)/t = kma --------------- (i)
*Here a = [ (v – u)/t ] is the acceleration, which is the rate of change of velocity. The quantity, k is a constant of proportionality.
* The SI unit of force is kg m s-2 or newton, represented as N.
I hope helps you
Newton’s second law of motion states that the rate of change of momentum of an object is Proportional to the applied unbalanced force in the direction of force.
Prooving--
Suppose an object of mass, m is moving along a straight line with an initial velocity, u. It is uniformly accelerated to velocity, v in time, t by the application of a constant force, F throughout the time t.
The initial and final momentum of the object will be, p1 = mu and p2 = mv respectively.
The change in momentum = p2 – p1
Then
change in momentum = mv – mu
The change in momentum = m × (v – u).
The rate of change of momentum = m × (v – u)/t
the applied force, F ∝ m × (v – u)/t
F = km × (v – u)/t = kma --------------- (i)
*Here a = [ (v – u)/t ] is the acceleration, which is the rate of change of velocity. The quantity, k is a constant of proportionality.
* The SI unit of force is kg m s-2 or newton, represented as N.
I hope helps you
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