Question

explain please in details

Answer 1

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Answer 2

In this question first we will prove that area of tr(PQR)= 1/4 of area of tr(ABC)

To dot his we need to prove that ar (ΔPQR)= ar (ΔBQP)= ar(ΔAQR)= ar(ΔRPC)

NOW, since P and Q are midpoints of BC and AB respectively

→ PQ║AC and PQ=1/2AC= CR

→PQRC is a ║gm.

hence, diagonal PR divides it into 2 ≅ Δs.

so, ar (ΔPQR)= ar(ΔRPC)

similarly,ar (ΔPQR)= ar (ΔBQP)= ar(ΔAQR)= ar(ΔRPC)

therefore, ar (ΔPQR)= 1/4 × 64

                                  = 16cm

now similarly, we will prove that ar(ΔXYZ)= 1/4× ar(ΔPQR)

                                                                     = 1/4×16

                                                                     = 4 cm

thank u.....