explain please...
in this solution how a^2/bc + b^2/ca + C^2/ab came ,????
please tell
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Anonymous:
hii
Actually what happens here
as you have proved that a+b+c=0
they directly used the converse of the identity
since the identity revolves as a^3 + b^3 + c^3 = 3abc ,,,,, if and only a+b+c =0 and we haven proved that
so just we have to divide abc by the equation a^3 + b^3 + c^3 and directly the R.H.S IS 3
hey
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Take the LCM,
It will become,
(a^3 + b^3 + c^3)/abc
Now, a +b +c is 0...
So, a^3 + b^3 + c^3 is 3abc....
Hence this becomes,
3abc/abc
= 3
.
..
Comment if u still have any doubts
It will become,
(a^3 + b^3 + c^3)/abc
Now, a +b +c is 0...
So, a^3 + b^3 + c^3 is 3abc....
Hence this becomes,
3abc/abc
= 3
.
..
Comment if u still have any doubts
I think it's given in the question
we need to find a^2 /bc + b^2/ac + c^2/ab
Do u get it now ???
can u post the question ??
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