Question

Explain Projiecticle motion and also expressions for ma.H R etc

Answer 1

Heya!
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★Projectile Motion ★
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=> Projectile refers to a body that is thrown into space provided with some initial velocity and then it travels there under the influence of gravity alone .

• Trajectory of a projectile = the path conversed by a projectile is called its trajectory . The trajectory of a projectile is a _Parabola_.

• Time Period = It is the time taken to traverse the path by the projeticler.

✔ T = √ 2h/g

✔T = 2u sin∅/g ( Angular )

• Horizontal Range = The maximum horizontal distance covered by a projectile is called the horizontal Range . It is represented by R.

✔R = u √2h/g

✔R = u²sin²∅/2g ( Angular )

•Maximum Height Hmax. = The maximum height attained by a projectile is called maximum height .

✔ Hmax. = u²/g sin2∅

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Answer 2

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Here is your answer
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$\textbf{Projectile Motion :}$

It is a name given to a body thrown with some initial velocity with a horizontal direction and then allowed to move in a 2 dimension under the action of gravity alone without being propelled by an external agent like engine...

OR

When an object is thrown with some initial horizontal velocity and around to move under the effect of gravity along without being propelled by an external agent like engine. The path of the projectile is known as trajectory...

→ Projectile in horizontal projection :-

» Path of projectile...

In x-axis

t = $\dfrac{x}{u}$

In y-axis

y = $\dfrac{1}{2} g \frac{ {x}^{2} }{{u}^{2} }$

y = kx²

» Time of flight...

Denoted by T

$T$ = $\sqrt{ \dfrac{2h}{g} }$

» Horizontal Range...

Denoted by R

$R$ = $u \sqrt{ \dfrac{2h}{g} }$

» Velocity of object at any instant...

v = $\sqrt{ {u}^{2} \: + \: {g}^{2} {t}^{2} }$

and

$\beta \: = \: { \tan }^{ - 1} ( \frac{ v(y) }{ v(x) } )$

→ Oblique projection or Angular projection :-

» Path of projectile...

In x-axis..

x = (u cosø) t

t = $\dfrac{x}{u \: \cos( \theta) }$

In y-axis...

y = x tanØ - $\dfrac{g {x}^{2} }{ 2{u}^{2} \cos( \theta) }$

» Time of flight...

T = $\dfrac{2u\:sin(\theta)}{g}$

» Maximum vertical height...

Denoted by H

H = $\dfrac{ {u}^{2} \: {sin}^{2} { \theta} }{2g}$

» Horizontal Range...

Denoted by R

R = $\dfrac{ {u}^{2} }{g}$ sin2Ø

» Maximum Horizontal Range...

Denoted by R

R = $\dfrac{ {u}^{2} }{g}$

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