Chemistry, asked by piyushsharma82paxg79, 7 months ago

Explain pyrolysis of benzene with chemical equation.


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Answered by Anonymous
8

Answer:

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The gas phase pyrolysis of benzene was studied in a static system in the range 873–1036 K. The reaction is largely homogeneous, of order 1.5 and involves free radicals. The products are diphenyl and hydrogen. The Arrhenius plot curves slightly at lower temperatures, but at higher temperatures the rate may be represented by d[h2]/dt=k[c6H6][fraction three-over-two]. where k= 109.83 exp (–225 kJ mol–1/RT) dm[fraction three-over-two] mol–½ s–1.

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I hope this helps you........

Answered by Anonymous
1

Answer:

The gas phase pyrolysis of benzene was studied in a static system in the range 873–1036 K. The reaction is largely homogeneous, of order 1.5 and involves free radicals. The products are diphenyl and hydrogen. The Arrhenius plot curves slightly at lower temperatures, but at higher temperatures the rate may be represented by d[h2]/dt=k[c6H6][fraction three-over-two]. where k= 109.83 exp (–225 kJ mol–1/RT) dm[fraction three-over-two] mol–½ s–1.

The gas phase pyrolysis of benzene was studied in a static system in the range 873–1036 K. The reaction is largely homogeneous, of order 1.5 and involves free radicals. The products are diphenyl and hydrogen. The Arrhenius plot curves slightly at lower temperatures, but at higher temperatures the rate may be represented by d[h2]/dt=k[c6H6][fraction three-over-two]. where k= 109.83 exp (–225 kJ mol–1/RT) dm[fraction three-over-two] mol–½ s–1..

The gas phase pyrolysis of benzene was studied in a static system in the range 873–1036 K. The reaction is largely homogeneous, of order 1.5 and involves free radicals. The products are diphenyl and hydrogen. The Arrhenius plot curves slightly at lower temperatures, but at higher temperatures the rate may be represented by d[h2]/dt=k[c6H6][fraction three-over-two]. where k= 109.83 exp (–225 kJ mol–1/RT) dm[fraction three-over-two] mol–½ s–1..I hope this helps you........

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