Question

explain pythagoras theorem plzzz

Answer 1

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a theorem attributed to Pythagoras that the square on the hypotenuse of a right-angled triangle is equal in area to the sum of the squares on the other two sides.

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Answer 2

Answer:

AC²= AB²+BC²

Step-by-step explanation:

> If a right triangle, the square of hypotenuse is equal to the sum of the square of other two sides.

GIVEN:

∆ABC right angle at B

TO PROVE:

AC²= AB² + BC²

CONSTRUCTION:

Draw BD perpendicular AC

PROOF:

Since BD perpendicular AC

∆ADB~∆ABC

Since , sides of similar triangles are in the same ratio,

- AD/AB = AB/AC

- AD. AC = AB².....(1)

∆BDC~∆ABC

Since , sides of similar triangles are in the same ratio,

- CD/BC = BC/AC

- CD. AC = BC²......(2)

Adding (1) & (2)

AD . AC + CD . AC = AB² + BC²

AC(AD + CD ) = AB² + BC²

AC × AC = AB² + BC²

AC² = AB² + BC²

HENCE PROVED...