Biology, asked by ak2998058, 7 months ago

Explain reason and consequences of increased and decreased peristaltic movement of GIT

Answers

Answered by nightfury27

Explanation:

The problem with your digestive muscles can be due to one of two causes: A problem within the muscle that controls peristalsis. A problem with the nerves or hormones that govern the muscle's contractions

Answered by adgupta1211

Explanation:

Let

Let 3+4i

Let 3+4i =

Let 3+4i = x

Let 3+4i = x +i

Let 3+4i = x +i y

Let 3+4i = x +i y Then (

Let 3+4i = x +i y Then ( 3+4i

Let 3+4i = x +i y Then ( 3+4i )

Let 3+4i = x +i y Then ( 3+4i ) 2

Let 3+4i = x +i y Then ( 3+4i ) 2 =(

Let 3+4i = x +i y Then ( 3+4i ) 2 =( x

Let 3+4i = x +i y Then ( 3+4i ) 2 =( x +i

Let 3+4i = x +i y Then ( 3+4i ) 2 =( x +i y

Let 3+4i = x +i y Then ( 3+4i ) 2 =( x +i y )

Let 3+4i = x +i y Then ( 3+4i ) 2 =( x +i y ) 2

Let 3+4i = x +i y Then ( 3+4i ) 2 =( x +i y ) 2 ⇒3+4i=x−y+2i

Let 3+4i = x +i y Then ( 3+4i ) 2 =( x +i y ) 2 ⇒3+4i=x−y+2i xy

Let 3+4i = x +i y Then ( 3+4i ) 2 =( x +i y ) 2 ⇒3+4i=x−y+2i xy Comparing real part and imaginary part, we get

Let 3+4i = x +i y Then ( 3+4i ) 2 =( x +i y ) 2 ⇒3+4i=x−y+2i xy Comparing real part and imaginary part, we get3=x−y and 2

Let 3+4i = x +i y Then ( 3+4i ) 2 =( x +i y ) 2 ⇒3+4i=x−y+2i xy Comparing real part and imaginary part, we get3=x−y and 2 xy

Let 3+4i = x +i y Then ( 3+4i ) 2 =( x +i y ) 2 ⇒3+4i=x−y+2i xy Comparing real part and imaginary part, we get3=x−y and 2 xy =4⇒xy=4

Let 3+4i = x +i y Then ( 3+4i ) 2 =( x +i y ) 2 ⇒3+4i=x−y+2i xy Comparing real part and imaginary part, we get3=x−y and 2 xy =4⇒xy=4∴x+y=±5 ( As x

Let 3+4i = x +i y Then ( 3+4i ) 2 =( x +i y ) 2 ⇒3+4i=x−y+2i xy Comparing real part and imaginary part, we get3=x−y and 2 xy =4⇒xy=4∴x+y=±5 ( As x 

Let 3+4i = x +i y Then ( 3+4i ) 2 =( x +i y ) 2 ⇒3+4i=x−y+2i xy Comparing real part and imaginary part, we get3=x−y and 2 xy =4⇒xy=4∴x+y=±5 ( As x  =−5;

Let 3+4i = x +i y Then ( 3+4i ) 2 =( x +i y ) 2 ⇒3+4i=x−y+2i xy Comparing real part and imaginary part, we get3=x−y and 2 xy =4⇒xy=4∴x+y=±5 ( As x  =−5; x

Let 3+4i = x +i y Then ( 3+4i ) 2 =( x +i y ) 2 ⇒3+4i=x−y+2i xy Comparing real part and imaginary part, we get3=x−y and 2 xy =4⇒xy=4∴x+y=±5 ( As x  =−5; x is real part )

Let 3+4i = x +i y Then ( 3+4i ) 2 =( x +i y ) 2 ⇒3+4i=x−y+2i xy Comparing real part and imaginary part, we get3=x−y and 2 xy =4⇒xy=4∴x+y=±5 ( As x  =−5; x is real part )∴x=4,y=1⇒

Let 3+4i = x +i y Then ( 3+4i ) 2 =( x +i y ) 2 ⇒3+4i=x−y+2i xy Comparing real part and imaginary part, we get3=x−y and 2 xy =4⇒xy=4∴x+y=±5 ( As x  =−5; x is real part )∴x=4,y=1⇒ x

Let 3+4i = x +i y Then ( 3+4i ) 2 =( x +i y ) 2 ⇒3+4i=x−y+2i xy Comparing real part and imaginary part, we get3=x−y and 2 xy =4⇒xy=4∴x+y=±5 ( As x  =−5; x is real part )∴x=4,y=1⇒ x =±2,y=±1

Let 3+4i = x +i y Then ( 3+4i ) 2 =( x +i y ) 2 ⇒3+4i=x−y+2i xy Comparing real part and imaginary part, we get3=x−y and 2 xy =4⇒xy=4∴x+y=±5 ( As x  =−5; x is real part )∴x=4,y=1⇒ x =±2,y=±1Hence square root is ±(2+i)

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