Question

Explain Reimer–Tiemann reaction !!!!...​

Answer 1

Answer:-

When phenols i.e. C6H5OH is treated with CHCl3 (chloroform) in the presence of NaOH (sodium hydroxide), an aldehyde group (-CHO) is introduced at the ortho position of benzene ring leading to the formation of o-hydroxybenzaldehyde. The reaction is popularly known as Reimer Tiemann reaction.